Difficulty: Easy
Correct Answer: Correct
Explanation:
Introduction / Context:
A pull-up resistor is one of the most common passive components in digital circuits. It prevents undefined or “floating” logic levels on inputs or on wired-OR/open-drain style outputs whenever no active device is driving the line LOW. This question checks whether you understand the role of a pull-up and why it results in a stable logic HIGH under idle conditions.
Given Data / Assumptions:
Concept / Approach:
Connect a resistor from the node to the positive supply (Vcc). When no device asserts a LOW, a small current through the resistor biases the node to Vcc, interpreting as logic 1. When an active device pulls the line LOW, the device sinks current through the pull-up, forcing a logic 0 within safe current limits. Value selection balances noise immunity, rise time, and current consumption.
Step-by-Step Solution:
Model the node as an input with very high impedance.Attach R to Vcc; node rises toward Vcc → interpreted as HIGH.Add an active pull-down driver; it sinks current I = (Vcc - VOL) / R, driving a valid LOW.When driver releases the line, the node returns HIGH via the resistor.
Verification / Alternative check:
Scope measurements show the node sitting near Vcc when idle and transitioning to a valid LOW when a driver engages. Data sheets show recommended pull-up values (for example, 1 kΩ–100 kΩ depending on speed and family).
Why Other Options Are Wrong:
“Incorrect” ignores the standard definition. Technology-specific choices (TTL vs. CMOS or open-collector only) are too narrow; pull-ups are used widely wherever a passive HIGH bias is needed.
Common Pitfalls:
Selecting too large a resistor causes slow rising edges and susceptibility to noise; too small wastes current and can overstress drivers. Forgetting that inputs should never be left floating is another frequent error.
Final Answer:
Correct
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