Difficulty: Easy
Correct Answer: The same at every point on its line of action (unchanged effect)
Explanation:
Introduction / Context:The principle of transmissibility enables engineers to move a force along its own line of action without changing the external effect on a rigid body. This simplifies free-body diagrams and statics reductions, provided the body can be treated as perfectly rigid.
Given Data / Assumptions:
Concept / Approach:
Forces that share the same line of action are statically equivalent in their external effect on a rigid body. Moving the point of application along the line of action does not change the resultant force or net moment about any external point; internal stress distributions can differ, but statics problems focus on external effects.
Step-by-Step Solution:
Identify the force vector F and its line of action.Shift F along the same line so that position vector r changes only along the line.Moment M_O = r × F remains unchanged for any external point O when the shift is collinear with F.Verification / Alternative check:
Compare net force and net moment before and after shifting: both are identical; hence, external equilibrium and reactions are unchanged.
Why Other Options Are Wrong:
(a) and (d) incorrectly tie effectiveness to C.G.; (b) contradicts the principle; (e) is inapplicable.
Common Pitfalls:
Applying transmissibility to deformable bodies where internal effects matter; confusing shifting along the line of action with moving off the line, which introduces a couple.
Final Answer:
The same at every point on its line of action (unchanged effect)
Discussion & Comments