Difficulty: Easy
Correct Answer: the clock pulse transitions from LOW to HIGH
Explanation:
Introduction / Context:Edge-triggered flip-flops are fundamental memory elements in synchronous digital systems. Unlike level-sensitive latches, they sample their inputs only at a fleeting instant defined by the clock transition. Understanding precisely when a positive edge-triggered S–R (Set–Reset) flip-flop latches its inputs prevents race conditions, timing violations, and misinterpretation of waveforms during debugging.
Given Data / Assumptions:
Concept / Approach:An edge-triggered device uses a pulse transition detector internally so that input sampling occurs only during an infinitesimal window at the clock's specified edge. For a positive edge-triggered device, that window is the rising edge (LOW→HIGH). Provided setup and hold constraints are met, the state after the edge remains stable until the next active clock edge, regardless of subsequent input chatter.
Step-by-Step Solution:
1) Identify the triggering characteristic: positive edge-triggered.2) Map this to a timing event: the active instant is the clock's LOW-to-HIGH transition.3) Determine behavior: outputs reflect S/R evaluated at that instant and then hold.4) Confirm that during HIGH or LOW levels (between edges), an ideal edge-triggered FF ignores input changes (subject to setup/hold timing).Verification / Alternative check:Examine a timing diagram: vary S and R safely before the rising edge (meeting setup time), keep them stable briefly after (meeting hold time), and observe Q updates exactly at the rising edge.
Why Other Options Are Wrong:
Common Pitfalls:Violating setup/hold around the edge, assuming outputs track inputs while the clock is HIGH, or confusing edge-triggered flip-flops with level-sensitive latches.
Final Answer:the clock pulse transitions from LOW to HIGH
Discussion & Comments