Difficulty: Easy
Correct Answer: 4 GB
Explanation:
Introduction / Context:
The number of address lines determines the maximum directly addressable memory space. For a processor with a 32-bit physical address bus, the theoretical addressable range is a key design constraint for operating systems and hardware designers.
Given Data / Assumptions:
Concept / Approach:
The physical address space equals 2^(number of address lines). With 32 address lines, that becomes 2^32 byte addresses. Converting 2^32 bytes gives 4,294,967,296 bytes, which equals 4 GB. System implementations may reserve ranges for memory-mapped I/O, but the theoretical maximum remains 4 GB for a 32-bit physical address bus.
Step-by-Step Solution:
Verification / Alternative check:
Motherboard documentation from the Pentium era commonly lists 4 GB as the maximum physical address range, with practical limits based on chipset and DIMM support.
Why Other Options Are Wrong:
1 MB reflects early 20-bit address spaces (8086 real mode). 1 GB and 2 GB are subsets of the full 4 GB capability.
Common Pitfalls:
Confusing virtual address space limits with physical addressable memory; operating system choices do not change the bus width capability.
Final Answer:
4 GB
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