Parallel resonance quality factor — is it correct that the Q of a parallel resonant circuit at resonance equals VC/VS or VL/VS (ratio of reactive branch voltage to source voltage)?

Difficulty: Easy

Correct Answer: False

Explanation:


Introduction / Context:
Quality factor (Q) measures selectivity and energy storage relative to loss. Its definition and practical expressions differ between series and parallel resonant circuits. This item checks a common misconception about using a simple voltage ratio for Q in parallel resonance.


Given Data / Assumptions:

  • Parallel RLC at resonance (admittance is purely real).
  • Reactive branch voltages equal the applied source voltage in parallel topology.
  • Realistic losses exist in R, L, and C.


Concept / Approach:
In a series resonant circuit, reactive element voltages can be much larger than the source voltage, and ratios like VL/VR can relate to Q (e.g., Q = XL/R). In a parallel resonant circuit, each branch is directly across the source, so VC ≈ VS and VL ≈ VS at resonance; the ratios VC/VS or VL/VS are about 1, not equal to Q. For parallel resonance, Q is more naturally expressed via currents (reactive branch current to source current) or via reactive/real power in the tank.


Step-by-Step Solution:

1) Recognize parallel topology: branch voltages equal source voltage.2) Therefore VC/VS ≈ 1 and VL/VS ≈ 1 at resonance.3) Q in parallel is often Q = I_reactive / I_source (or related to susceptance vs conductance).4) Conclude the proposed voltage ratios do not represent Q for parallel circuits.


Verification / Alternative check:
Tank circuits exhibit large circulating reactive currents at resonance while source current is minimal; this current ratio aligns with Q, not a voltage ratio of ~1.


Why Other Options Are Wrong:

“True/True only…”: conflict with parallel topology where branch voltages equal the source.“Depends solely on ESR”: Q depends on aggregate losses, not exclusively capacitor ESR.


Common Pitfalls:
Transferring series-circuit voltage relationships directly to parallel tanks.


Final Answer:
False

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