Difficulty: Easy
Correct Answer: False
Explanation:
Introduction / Context:Quality factor (Q) measures selectivity and energy storage relative to loss. Its definition and practical expressions differ between series and parallel resonant circuits. This item checks a common misconception about using a simple voltage ratio for Q in parallel resonance.
Given Data / Assumptions:
Concept / Approach:In a series resonant circuit, reactive element voltages can be much larger than the source voltage, and ratios like VL/VR can relate to Q (e.g., Q = XL/R). In a parallel resonant circuit, each branch is directly across the source, so VC ≈ VS and VL ≈ VS at resonance; the ratios VC/VS or VL/VS are about 1, not equal to Q. For parallel resonance, Q is more naturally expressed via currents (reactive branch current to source current) or via reactive/real power in the tank.
Step-by-Step Solution:
1) Recognize parallel topology: branch voltages equal source voltage.2) Therefore VC/VS ≈ 1 and VL/VS ≈ 1 at resonance.3) Q in parallel is often Q = I_reactive / I_source (or related to susceptance vs conductance).4) Conclude the proposed voltage ratios do not represent Q for parallel circuits.Verification / Alternative check:Tank circuits exhibit large circulating reactive currents at resonance while source current is minimal; this current ratio aligns with Q, not a voltage ratio of ~1.
Why Other Options Are Wrong:
“True/True only…”: conflict with parallel topology where branch voltages equal the source.“Depends solely on ESR”: Q depends on aggregate losses, not exclusively capacitor ESR.Common Pitfalls:Transferring series-circuit voltage relationships directly to parallel tanks.
Final Answer:False
Discussion & Comments