Series RLC reactance — when both inductive reactance (XL) and capacitive reactance (XC) are present in the same series circuit, is the magnitude of total reactance equal to the sum of their magnitudes?

Difficulty: Easy

Correct Answer: False — |X| = |XL − XC|

Explanation:


Introduction / Context:
Understanding how reactances combine in series is essential for predicting a circuit’s impedance and phase. This question distinguishes the correct rule for combining inductive and capacitive reactances in a series path.


Given Data / Assumptions:

  • Single series path containing L and C (and possibly R).
  • Steady-state sinusoidal operation at angular frequency ω.


Concept / Approach:
In series, reactances add algebraically: X_total = XL + (−XC). Therefore, X_total = XL − XC. The magnitude is |X_total| = |XL − XC|, not the sum of magnitudes. At resonance, XL = XC and the net reactance magnitude becomes zero (ideal case), leaving purely resistive impedance.


Step-by-Step Solution:

1) Compute XL = ωL and XC = 1/(ωC).2) Sum algebraically: X_total = XL − XC.3) Take magnitude: |X| = |XL − XC|.4) Interpret: if XL > XC, net is inductive; if XC > XL, net is capacitive.


Verification / Alternative check:
Bode/phasor diagrams show the vector subtraction along the imaginary axis, not a scalar sum of lengths.


Why Other Options Are Wrong:

Sum of magnitudes: overestimates reactance and ignores the opposite signs of XL and XC.“Only at resonance/only for small R/ideal inductors”: the combination rule is general for sinusoidal steady state.


Common Pitfalls:
Adding magnitudes instead of algebraic quantities; forgetting that capacitive reactance is negative in phasor notation.


Final Answer:
False — |X| = |XL − XC|

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