Difficulty: Easy
Correct Answer: False — |X| = |XL − XC|
Explanation:
Introduction / Context:
Understanding how reactances combine in series is essential for predicting a circuit’s impedance and phase. This question distinguishes the correct rule for combining inductive and capacitive reactances in a series path.
Given Data / Assumptions:
Concept / Approach:
In series, reactances add algebraically: X_total = XL + (−XC). Therefore, X_total = XL − XC. The magnitude is |X_total| = |XL − XC|, not the sum of magnitudes. At resonance, XL = XC and the net reactance magnitude becomes zero (ideal case), leaving purely resistive impedance.
Step-by-Step Solution:
Verification / Alternative check:
Bode/phasor diagrams show the vector subtraction along the imaginary axis, not a scalar sum of lengths.
Why Other Options Are Wrong:
Common Pitfalls:
Adding magnitudes instead of algebraic quantities; forgetting that capacitive reactance is negative in phasor notation.
Final Answer:
False — |X| = |XL − XC|
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