Series RLC reactance — when both inductive reactance (XL) and capacitive reactance (XC) are present in the same series circuit, is the magnitude of total reactance equal to the sum of their magnitudes?

Electronics RLC Circuits and Resonance Difficulty: Easy
Choose an option
  • A
    True — |X| = |XL| + |XC|
  • B
    False — |X| = |XL − XC|
  • C
    True only at resonance
  • D
    True only for very small R
  • E
    True only for ideal inductors

Answer

Correct Answer: False — |X| = |XL − XC|

Explanation

Introduction / Context:Understanding how reactances combine in series is essential for predicting a circuit’s impedance and phase. This question distinguishes the correct rule for combining inductive and capacitive reactances in a series path.

Given Data / Assumptions:

  • Single series path containing L and C (and possibly R).
  • Steady-state sinusoidal operation at angular frequency ω.

Concept / Approach:In series, reactances add algebraically: X_total = XL + (−XC). Therefore, X_total = XL − XC. The magnitude is |X_total| = |XL − XC|, not the sum of magnitudes. At resonance, XL = XC and the net reactance magnitude becomes zero (ideal case), leaving purely resistive impedance.

Step-by-Step Solution:

1) Compute XL = ωL and XC = 1/(ωC).2) Sum algebraically: X_total = XL − XC.3) Take magnitude: |X| = |XL − XC|.4) Interpret: if XL > XC, net is inductive; if XC > XL, net is capacitive.

Verification / Alternative check:Bode/phasor diagrams show the vector subtraction along the imaginary axis, not a scalar sum of lengths.

Why Other Options Are Wrong:

Sum of magnitudes: overestimates reactance and ignores the opposite signs of XL and XC.“Only at resonance/only for small R/ideal inductors”: the combination rule is general for sinusoidal steady state.

Common Pitfalls:Adding magnitudes instead of algebraic quantities; forgetting that capacitive reactance is negative in phasor notation.

Final Answer:False — |X| = |XL − XC|

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