Digital logic: an OR gate has two or more inputs. According to the standard truth table, if any one (or more) input is high (logic 1), what is the output state?

Introduction / Context:
Basic gates (AND, OR, NOT) form the foundation of digital logic. The OR gate outputs a logic 1 whenever one or more of its inputs are at logic 1, capturing the inclusive “or” operation used throughout combinational circuits. Mastering this truth table is essential for designing and analyzing larger systems.

Given Data / Assumptions:

• We consider conventional positive logic (high = 1, low = 0).
• OR gate has two or more inputs.
• We evaluate the output when any single input is high.

Concept / Approach:
The OR function is defined as output = 1 if at least one input = 1, else output = 0. This is inclusive OR (not XOR). Therefore, the correct state when any input is high is “high.” Options stating “low” or “0” contradict the gate’s truth table.

Step-by-Step Solution:
Recall truth table: for inputs A, B, …, output Y = A OR B OR …If any input = 1, then Y = 1.Therefore, the output is high.Select “high.”

Verification / Alternative check:
Construct a quick table for two inputs: (0,0)→0; (0,1)→1; (1,0)→1; (1,1)→1. This generalizes to more inputs.

Why Other Options Are Wrong:
low / 0: the OR function would output 1 when any input is 1, not 0.All of the above: impossible because “low” and “high” cannot both be correct simultaneously.None: incorrect because “high” is correct.

Common Pitfalls:
Confusing inclusive OR with exclusive OR; mixing active-low logic conventions; misreading multi-input truth tables.

Final Answer:
high