By definition of the newton in S.I., one newton of force produces which acceleration on a body of specified mass?

Introduction / Context:
The newton (N) is the S.I. unit of force. Its definition anchors many engineering calculations in statics and dynamics, ensuring that F = m * a has a clear numerical interpretation in base units. Selecting the correct pairing of mass and acceleration cements the meaning of 1 N in everyday calculations.

Given Data / Assumptions:

• S.I. base units: kilogram (kg) for mass, metre (m) for length, second (s) for time.
• Newton's second law: F = m * a.
• 1 N corresponds to a particular acceleration produced on a 1 kg mass.

Concept / Approach:

From F = m * a, set F = 1 N and m = 1 kg to solve for a. This provides the definition of the newton in S.I. terms without resorting to gravitational units or centimetre–gram–second scales.

Step-by-Step Solution:

Verification / Alternative check:

Dimensional analysis: N = kg*m/s^2, which rearranges to a = N/kg = m/s^2, confirming the numerical result for unit values.

Why Other Options Are Wrong:

• 1 cm/s^2 cases: Use centimetre-based acceleration, not the S.I. metre per second squared; also mixes g and kg inconsistently.
• 1 m/s^2 on 1 g mass: Uses gram, a C.G.S. mass unit, not S.I.
• 10 m/s^2 on 1 kg: Would imply a 10 N force, not 1 N.

Common Pitfalls:

• Switching to centimetres or grams mid-calculation, causing hidden 10× or 1000× errors.
• Confusing weight (in N) with mass (in kg) when applying F = m * a.

Final Answer:

1 m/s^2 while acting on a body of 1 kg mass