Electrical measurements: identify the correct S.I. unit for the intensity of electric current.

Difficulty: Easy

Correct Answer: Amperes

Explanation:


Introduction / Context:
Electrical quantities have distinct meanings and S.I. units. Current (the rate of flow of electric charge) is foundational in circuit theory, power systems, and electronics. Using its correct unit keeps Ohm’s law, power equations, and continuity relations dimensionally consistent.


Given Data / Assumptions:

  • Current I is defined as charge flow per unit time: I = dQ/dt.
  • Charge Q is measured in coulombs (C).
  • Time is in seconds (s).


Concept / Approach:
From I = dQ/dt, the unit is C/s. The S.I. special name for C/s is ampere (A). Other electrical quantities—voltage (V), power (W), energy (J)—are related but not interchangeable. Correct unit selection simplifies analysis of DC/AC circuits, transient behavior, and instrumentation readings.


Step-by-Step Solution:

Start with definition: I = dQ/dt.Substitute units: Q → C; t → s; so I units → C/s.Recognize C/s as ampere (A): the S.I. base unit for electric current.


Verification / Alternative check:

Ohm’s law V = I * R: V (volt) = A * Ω. Power P = V * I = W, confirming consistent unit relations.


Why Other Options Are Wrong:

Volts: electric potential difference.Watts: power (rate of energy transfer).Joules: energy.Coulombs: quantity of charge, not rate of flow.


Common Pitfalls:

Confusing coulomb (charge) with ampere (current).Treating voltage as “strength of current,” which conflates potential difference with flow rate.


Final Answer:

Amperes

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