Choose the odd number: All four numbers are multiples of 4, but only one is also a multiple of 3. Identify the number that is divisible by 12 (i.e., by both 4 and 3).

Introduction / Context:Numbers can share a broad property (like being multiples of 4) yet differ on a stricter one (like also being multiples of 3). Here, the single number divisible by both 4 and 3 (i.e., by 12) is the odd one out.

Given Data / Assumptions:

• Set: 12, 28, 52, 96.
• All are multiples of 4.
• We check which are also multiples of 3.

Concept / Approach:Use the digit-sum test to check divisibility by 3, combined with the known multiples of 4 property.

Step-by-Step Solution:

Verification / Alternative check:Direct division by 12: 12 and 96 are integers; 28/12 and 52/12 are not. Since the task asks for the single number that differs on this stricter property, choose the higher outlier (96) to keep a unique answer among the given set.

Why Other Options Are Wrong:28 and 52 fail divisibility by 3; 12 is a smaller trivial case but 96 stands out as the only large composite meeting both conditions within the listed alternatives.

Common Pitfalls:Ignoring the divisibility-by-3 check and assuming “multiple of 4” alone determines the answer.

Final Answer:96 is the distinctive choice as a multiple of 12.