You have a network with a subnet of 172.16.17.0/22. Which is the valid host address?

172.16.17.1 255.255.255.252
172.16.0.1 255.255.240.0
172.16.20.1 255.255.254.0
172.16.18.255 255.255.252.0

Correct Answer: 172.16.18.255 255.255.252.0

Explanation:

A Class B network ID with a /22 mask is 255.255.252.0, with a block size of 4 in the third octet. The network address in the question is in subnet 172.16.16.0 with a broadcast address of 172.16.19.255. Only option E even has the correct subnet mask listed, and 172.16.18.255 is a valid host.

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