Choose a valid server IP: Subnet is 192.168.19.24/29. The router uses the first available host address. Which IP/mask should you assign to the server on this subnet?

Difficulty: Medium

Correct Answer: 192.168.19.26 255.255.255.248

Explanation:


Introduction / Context:
Assigning host addresses requires understanding the subnet range and avoiding the network, broadcast, and already-allocated addresses. /29 subnets are small and easy to enumerate.



Given Data / Assumptions:

  • Subnet: 192.168.19.24/29 (mask 255.255.255.248)
  • Router has the first usable host in the subnet.


Concept / Approach:
A /29 gives 8 addresses: network, 6 hosts, broadcast. For the 24/29 block, hosts run from .25 to .30 if .24 is the network and .31 is broadcast. The router, using the first host, takes .25, so pick another host such as .26.



Step-by-Step Solution:

Network = 192.168.19.24; Broadcast = 192.168.19.31.Usable hosts: .25–.30; router uses .25.Select a remaining host: 192.168.19.26 with mask 255.255.255.248.


Verification / Alternative check:
Count addresses (8 total), confirm .26 falls between network and broadcast and is not already assigned to the router.



Why Other Options Are Wrong:

  • A: Different network and mask.
  • B: .33 is not in the 24/29 block; mask /28 also wrong.
  • D: .31 is the broadcast for this /29.
  • E: .25 is already taken by the router per the scenario.


Common Pitfalls:
Misreading the block size; forgetting that the first usable address is already allocated.



Final Answer:
192.168.19.26 255.255.255.248

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