Difficulty: Medium
Correct Answer: 192.168.19.26 255.255.255.248
Explanation:
Introduction / Context:
Assigning host addresses requires understanding the subnet range and avoiding the network, broadcast, and already-allocated addresses. /29 subnets are small and easy to enumerate.
Given Data / Assumptions:
Concept / Approach:
A /29 gives 8 addresses: network, 6 hosts, broadcast. For the 24/29 block, hosts run from .25 to .30 if .24 is the network and .31 is broadcast. The router, using the first host, takes .25, so pick another host such as .26.
Step-by-Step Solution:
Verification / Alternative check:
Count addresses (8 total), confirm .26 falls between network and broadcast and is not already assigned to the router.
Why Other Options Are Wrong:
Common Pitfalls:
Misreading the block size; forgetting that the first usable address is already allocated.
Final Answer:
192.168.19.26 255.255.255.248
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