Broadcast address determination: An interface has IP 192.168.192.10/29. What broadcast address will hosts on this LAN use?

Introduction / Context:For any subnet, the broadcast address is the highest address in that block. With /29, determining the 8-address block is straightforward and frequently tested.

Given Data / Assumptions:

• Host: 192.168.192.10/29
• /29 mask = 255.255.255.248 (block size 8)

Concept / Approach:Identify the /29 block containing .10 by finding the nearest lower multiple of 8 and then adding 7 for the broadcast address.

Step-by-Step Solution:

Verification / Alternative check:Compute: 10 - (10 mod 8) = 8; broadcast = 8 + 7 = 15.

Why Other Options Are Wrong:

• .31/.63/.127: Broadcasts for larger subnets (/27, /26, /25), not /29.
• .11: A valid host, not the broadcast.

Common Pitfalls:Forgetting that /29 uses 8-address blocks; misidentifying the correct block around the host.

Final Answer:192.168.192.15