IPv4 subnetting practice: What is the subnetwork (network) address for a host with IP address 200.10.5.68/28?

Introduction / Context:Subnetting with Classless Inter-Domain Routing (CIDR) requires identifying the block size and then finding the exact network address that contains a given host IP. Here we are working with a /28 prefix, a common exam scenario.

Given Data / Assumptions:

• Host IP: 200.10.5.68/28
• /28 corresponds to mask 255.255.255.240
• We seek the network (subnetwork) address for that host

Concept / Approach:The block size is determined by 256 minus the last-octet mask value. For /28, the last octet mask is 240, so the block size is 256 - 240 = 16. Valid network boundaries occur at increments of 16 in the fourth octet: 0, 16, 32, 48, 64, 80, etc.

Step-by-Step Solution:

Verification / Alternative check:Compute: 68 - (68 mod 16) = 68 - 4 = 64, confirming the network base.

Why Other Options Are Wrong:

• 200.10.5.56: 56 is not a /28 boundary (16-multiple) for this range.
• 200.10.5.32 and 200.10.5.0: Different /28 networks; do not contain 68.
• 200.10.5.80: Next network boundary above 68, not the one containing it.

Common Pitfalls:Mixing up /28 with /29 block sizes; forgetting boundaries must be exact multiples of the block size.

Final Answer:200.10.5.64