Which of the following is the valid host range for the subnet on which the IP address 192.168.168.188 255.255.255.192 resides?
Correct Answer: 192.168.168.129-190
Explanation:
256 - 192 = 64. 64 + 64 = 128. 128 + 64 = 192. The subnet is 128, the broadcast address is 191, and the valid host range is the numbers in between, or 129-190.
