Difficulty: Easy
Correct Answer: 1 : 3
Explanation:
Introduction / Context:
Price alligation problems find the mixing proportion of costlier and cheaper grades for a desired mean price.
Given Data / Assumptions:
Concept / Approach:
Alligation rule: quantity ratio (cheaper:dearer) = (dearer − mean) : (mean − cheaper) = (300 − 225) : (225 − 200) = 75 : 25 = 3 : 1. Question asks for 300:200 (dearer:cheaper); invert to 1 : 3.
Step-by-Step Solution:
1) Compute differences from mean.2) Obtain cheaper:dearer = 3:1.3) Convert to asked order (300:200) ⇒ 1:3.
Verification / Alternative check:
Weighted average with 1 part ₹300 and 3 parts ₹200: (1*300 + 3*200)/4 = (300 + 600)/4 = 900/4 = 225.
Why Other Options Are Wrong:
3:1 or 4:1 would raise mean above ₹225; 1:4 would lower it below ₹225.
Common Pitfalls:
Reporting the ratio in the wrong order (cheaper:dearer instead of dearer:cheaper).
Final Answer:
1 : 3
Discussion & Comments