Milk–water mixture parts 11:2:\nAfter adding 35 L water, the mixture contains twice as much milk as water. Find original pure milk (L).

Difficulty: Medium

Correct Answer: 110

Explanation:


Introduction / Context:
Given a parts ratio and an addition of water, enforce the final condition milk = 2*water to find original quantities.


Given Data / Assumptions:

  • Original milk:water = 11:2 ⇒ milk = 11k, water = 2k.
  • Add 35 L water ⇒ final water = 2k + 35.
  • Final condition: milk = 2*(final water).


Concept / Approach:
11k = 2*(2k + 35) ⇒ solve k, then compute milk = 11k.


Step-by-Step Solution:

11k = 4k + 70 ⇒ 7k = 70 ⇒ k = 10.Original milk = 11k = 110 L.


Verification / Alternative check:
Original water 20 L; after addition 55 L; milk 110 L is indeed twice water 55 L.


Why Other Options Are Wrong:
55 is water after addition; 70, 220 mismatch the given condition.


Common Pitfalls:
Doubling the original water rather than the final water (which includes the added 35 L).


Final Answer:
110

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