Semiconductor carrier transport: Given minority-carrier lifetime τ = 100 μs and diffusion constant D = 100 cm^2/s, compute the diffusion length L of the carriers.
Electronics and Communication Engineering
Materials and Components
Difficulty: Easy
Choose an option
-
A0.1 cm
-
B0.01 cm
-
C0.0141 cm
-
D1 cm
-
E0.32 cm
Answer
Correct Answer: 0.1 cm
Explanation
Introduction / Context:The diffusion length L characterizes how far minority carriers can diffuse before recombining. It is a key parameter for device dimensions in photodiodes, solar cells, and bipolar transistors, linking material quality (lifetime) and transport (diffusion constant).
Given Data / Assumptions:
- Minority-carrier lifetime τ = 100 μs = 100 × 10^-6 s = 1 × 10^-4 s.
- Diffusion constant D = 100 cm^2/s.
- One-dimensional steady-state diffusion–recombination model.
Concept / Approach:
The diffusion length is L = sqrt(D * τ). Substituting the given values gives L in centimeters because D is in cm^2/s and τ in seconds.
Step-by-Step Solution:
Compute product: D * τ = 100 * (1 × 10^-4) = 1 × 10^-2 cm^2.Take square root: L = sqrt(1 × 10^-2) = 0.1 cm.Select the matching option: 0.1 cm.Verification / Alternative check:
Units: sqrt(cm^2) = cm, consistent. Orders of magnitude are typical for high-quality materials with long lifetimes.
Why Other Options Are Wrong:
- 0.01 cm and 0.0141 cm correspond to smaller D or τ; not matching the given data.
- 1 cm is an order of magnitude too large for the stated parameters.
- 0.32 cm would require D * τ ≈ 0.1024 cm^2, not given here.
Common Pitfalls:
- Mistaking μs for ms, which would inflate L by sqrt(10).
Final Answer:
0.1 cm