Difficulty: Easy
Correct Answer: A is true but R is false
Explanation:
Introduction / Context:Temperature sensitivity determines the stability of diodes and transistors. Silicon (Si) and germanium (Ge) differ in band gap and intrinsic carrier generation, producing different thermal behaviors and turn-on voltages.
Given Data / Assumptions:
Concept / Approach:The intrinsic carrier concentration n_i grows roughly as exp(−E_g/(2kT)). A larger E_g (silicon) yields much lower n_i and a smaller temperature coefficient of leakage and parameters. Hence Si is less temperature-sensitive than Ge — the assertion is true. The reason claims Si has a smaller cut-in voltage than Ge, which is false; Si's cut-in is larger.
Step-by-Step Solution:
Relate temperature sensitivity to band gap: larger E_g → lower n_i → better thermal stability.Check cut-in voltages: V_γ(Si) ≈ 0.7 V > V_γ(Ge) ≈ 0.3 V.Therefore A is true; R is false; R cannot explain A.Verification / Alternative check:
Leakage current vs. temperature curves show Ge rises much faster than Si, confirming higher sensitivity of Ge.Why Other Options Are Wrong:
Options claiming R true contradict measured diode characteristics; options stating A false contradict band-gap arguments.Common Pitfalls:
Confusing forward drop (cut-in) with thermal stability; they are related to material properties but not in the way stated by R.Final Answer:
A is true but R is false
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