The sum of the present ages of a father and son is 45 years. Five years ago, the product of their ages was four times the father's age at that time. What are their present ages?

Difficulty: Medium

Correct Answer: 36 years, 9 years

Explanation:

Introduction / Context:This mixes a present sum condition with a past product condition. The structure simplifies after factoring the past product equation.

Given Data / Assumptions:

  • Present ages: Father = f, Son = s
  • f + s = 45
  • Five years ago: (f − 5)(s − 5) = 4(f − 5)

Concept / Approach:Factor the past equation by taking (f − 5) common. This yields two possible cases; reject the infeasible one and use the sum to find both ages.

Step-by-Step Solution:

(f − 5)(s − 5) = 4(f − 5)(f − 5)[(s − 5) − 4] = 0 ⇒ (f − 5)(s − 9) = 0Either f = 5 (impossible for a father) or s = 9Thus s = 9 ⇒ f = 45 − 9 = 36

Verification / Alternative check:

Five years ago: f = 31, s = 4 ⇒ product = 124; 4(f − 5) = 4×31 = 124 ✓

Why Other Options Are Wrong:

  • 25,10 and 39,6 do not satisfy both conditions.
  • None of these and 28,17 are inconsistent with the factored constraint.

Common Pitfalls:Missing the factorization shortcut; choosing f = 5 despite being unrealistic; or misapplying the 5-year shift to only one age.

Final Answer:36 years, 9 years

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