On a transmission line, the measured magnitudes of the input impedance at open-circuit (Z_in,OC) and short-circuit (Z_in,SC) are 100 Ω and 25 Ω, respectively. The characteristic impedance Z0 is:
-
A25 Ω
-
B50 Ω
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C75 Ω
-
D100 Ω
Answer
Correct Answer: 50 Ω
Explanation
Introduction:For a (low-loss) transmission line section of unknown electrical length, the open-circuit and short-circuit input impedances can be used to determine the characteristic impedance Z0. This is a common lab technique in RF measurements.
Given Data / Assumptions:
- |Z_in,OC| = 100 Ω
- |Z_in,SC| = 25 Ω
- Assume a low-loss line so that |Z0| ≈ sqrt(|Z_in,OC| * |Z_in,SC|)
Concept / Approach:For a uniform line, Z0 can be obtained from the geometric mean of OC and SC input impedances: Z0 ≈ sqrt(Z_OC * Z_SC) (magnitude relation under low-loss assumption).
Step-by-Step Solution:
1) Compute product: 100 * 25 = 2500.2) Take square root: sqrt(2500) = 50.3) Therefore Z0 ≈ 50 Ω.Verification / Alternative check:Network analyzer methods and line calculators confirm that for practical low-loss coaxial lines, the geometric mean relation holds closely.
Why Other Options Are Wrong:
- A/D: 25 Ω and 100 Ω are the raw OC/SC magnitudes, not Z0.
- C: 75 Ω does not satisfy the geometric-mean relationship.
Common Pitfalls:Forgetting that this relationship applies to low-loss lines; mixing up arithmetic vs geometric mean.
Final Answer:50 Ω