Estimate the approximate half-power beamwidth (HPBW) of a 1 m diameter parabolic antenna operating at 1 GHz. (Use HPBW ≈ 70 * (lambda / D) degrees; lambda ≈ 0.3 m at 1 GHz.)
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A12°
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B18°
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C21°
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D24°
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E5°
Answer
Correct Answer: 21°
Explanation
Introduction:This problem evaluates your ability to estimate the beamwidth of a parabolic reflector from its diameter and operating frequency. Such quick estimates are vital in link budgeting and antenna siting.
Given Data / Assumptions:
- Parabolic antenna, diameter D = 1 m.
- Operating frequency f = 1 GHz ⇒ lambda ≈ 0.3 m.
- Empirical HPBW rule: HPBW ≈ 70 * (lambda / D) degrees for typical illumination.
Concept / Approach:
The beamwidth of a large-aperture antenna is inversely proportional to its electrical size (D / lambda). Increasing diameter narrows the beam; increasing wavelength (lower frequency) widens it.
Step-by-Step Solution:
1) Compute lambda = 0.3 m at 1 GHz.2) Compute lambda / D = 0.3 / 1 = 0.3.3) HPBW ≈ 70 * 0.3 = 21 degrees.4) Closest option is 21°, which directly matches the estimate.Verification / Alternative check:
Some texts use constants between 58 and 70 depending on taper and efficiency. Using 58 * (lambda / D) gives ≈ 17°. Both figures are of the same order, confirming that ≈ 21° is a reasonable estimate for typical illumination.
Why Other Options Are Wrong:
- 12°/18°/24°: plausible but deviate from the commonly used 70 * (lambda / D) estimate for a 1 m dish at 1 GHz.
- 5°: far too narrow for such a small dish at 1 GHz.
Common Pitfalls:
Confusing HPBW with first-null beamwidth (FNBW), which is roughly ~2 * HPBW. Choosing a constant without considering illumination taper can also skew results.
Final Answer:
21°