Machine-rate scaling: 6 identical machines produce 270 bottles per minute. At the same constant rate, how many bottles will 10 such machines produce in 4 minutes?

Difficulty: Easy

Correct Answer: 1800

Explanation:


Introduction / Context:
When identical machines work at a constant rate, output scales directly with both the number of machines and the time. Convert to per-machine output and then multiply up to the new count and duration.


Given Data / Assumptions:

  • 6 machines ⇒ 270 bottles/minute.
  • All machines are identical; rates are constant.
  • Find output for 10 machines in 4 minutes.


Concept / Approach:
Per-machine rate = total rate / number of machines. New total = per-machine rate * new machines * new time. Ensure units (minutes) are consistent.


Step-by-Step Solution:

Per-machine rate = 270 / 6 = 45 bottles/minute 10 machines ⇒ 10 * 45 = 450 bottles/minute In 4 minutes ⇒ 450 * 4 = 1800 bottles


Verification / Alternative check:
Proportionality: scaling machines by 10/6 and time by 4 multiplies output by (10/6)*4 = 6.666… ⇒ 270 * 6.666… = 1800, same result.


Why Other Options Are Wrong:
1600, 1700, 2000, 2500 do not match the linear scaling from 270 bottles/min for 6 machines.


Common Pitfalls:
Forgetting to multiply by time, or dividing by the wrong machine count when computing per-machine rate.


Final Answer:
1800

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