Logarithmic mean temperature difference (LMTD): Given inlet and outlet temperature differences Δt1 and Δt2 between hot and cold streams, the correct expression for the mean temperature difference is

Introduction / Context:The LMTD method is widely used in heat exchanger analysis to compute heat transfer rate when terminal temperatures are known. The right formula is essential for accurate design.

Given Data / Assumptions:

• Two fluids exchanging heat with constant overall heat transfer coefficient U and area A.
• Terminal temperature differences Δt1 and Δt2 at the two ends of the exchanger.
• No phase change and steady state for simplicity.

Concept / Approach:Since temperature difference varies exponentially along the length, the appropriate average is the logarithmic mean, not the arithmetic or geometric mean. Heat duty is Q = U * A * tm where tm = (Δt1 - Δt2) / ln(Δt1 / Δt2).

Step-by-Step Solution:Write local heat transfer: dQ = U * dA * Δt(x).Integrate along length using boundary conditions to derive tm.Obtain tm = (Δt1 - Δt2) / ln(Δt1 / Δt2).Use Q = U * A * tm to compute duty.

Verification / Alternative check:Limiting case Δt1 → Δt2 gives tm → Δt1 (using L’Hôpital’s rule), matching physical expectation of uniform Δt.

Why Other Options Are Wrong:

• Arithmetic or geometric means do not satisfy the exponential temperature profile implied by energy balance.
• ln(Δt1 * Δt2) and (Δt1 - Δt2) * ln(Δt1 / Δt2) are dimensionally or mathematically incorrect.

Common Pitfalls:Swapping Δt1 and Δt2 positions or using base-10 logarithm incorrectly (natural logarithm is standard in derivation).

Final Answer:tm = (Δt1 - Δt2) / ln(Δt1 / Δt2)