According to Newton’s law of cooling for convection, the heat transfer rate from a hotter body to a colder fluid is proportional to which factors?
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ASurface area only
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BTemperature difference only
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CEither surface area or temperature difference (exclusively)
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DThe product of surface area and temperature difference (both apply)
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EFluid density only
Answer
Correct Answer: The product of surface area and temperature difference (both apply)
Explanation
Introduction / Context:Newton’s law of cooling provides a linearized model for convective heat transfer near a surface. It is central to HVAC, electronics cooling, and thermal design, simplifying complex boundary-layer physics into an engineering correlation using a heat transfer coefficient.
Given Data / Assumptions:
- A solid surface at temperature T_s interacts with a fluid at T_∞.
- Heat transfer coefficient h captures flow, properties, and geometry effects.
- Area A is the effective heat-exchange surface.
Concept / Approach:Newton’s law states q = h * A * (T_s − T_∞). Thus, for a given h, heat transfer is directly proportional to both area A and the temperature difference ΔT. Therefore, the correct interpretation is that both factors simultaneously influence the rate, not one or the other exclusively.
Step-by-Step Solution:
1) Write the relation: q = h * A * (T_s − T_∞).2) Identify proportionalities: q ∝ A and q ∝ (T_s − T_∞).3) Conclude: proportional to the product A * ΔT for constant h.Verification / Alternative check:Dimensional reasoning confirms that doubling area or doubling temperature difference doubles q; doing both quadruples q if h is unchanged.
Why Other Options Are Wrong:
- Area only or ΔT only ignores the other factor.
- “Either/or exclusively” misunderstands the multiplicative dependence.
- Fluid density alone does not appear explicitly; its effect is embedded in h.
Common Pitfalls:Treating h as constant across large ΔT or different flow regimes; in reality, h may change, but the basic proportionality form remains valid.
Final Answer:The product of surface area and temperature difference (both apply)