With the lower refrigeration temperature fixed, which action improves the coefficient of performance (COP) of a refrigeration cycle?

Difficulty: Easy

Correct Answer: Lower the higher (condensing) temperature

Explanation:


Introduction / Context:
The coefficient of performance (COP) for a refrigerator is Q_L/W, where Q_L is heat removed at the low temperature and W is compressor work input. The temperature lift between evaporator and condenser largely determines the work required. Reducing this lift generally improves efficiency.


Given Data / Assumptions:

  • Evaporator (low) temperature is fixed by process/comfort requirement.
  • Condenser rejects heat to ambient; its temperature depends on heat exchanger effectiveness and ambient conditions.


Concept / Approach:
For an idealized reversed Carnot refrigerator, COP = T_L / (T_H − T_L). With T_L fixed, decreasing T_H increases COP. Practical vapor-compression systems follow the same trend: better heat rejection (lower condensing temperature via larger condenser, improved airflow, cooler ambient) reduces compression ratio and work input.


Step-by-Step Solution:

1) Note COP increases when temperature lift (T_H − T_L) decreases.2) With fixed T_L, the only lever is to lower T_H.3) Therefore, improved condenser performance or cooler ambient increases COP.


Verification / Alternative check:
Performance maps of compressors show lower power at lower condensing temperatures for the same evaporating condition, confirming the theoretical trend.


Why Other Options Are Wrong:

  • Changing speed alone does not guarantee higher COP; it affects capacity more than fundamental cycle efficiency.
  • Raising T_H increases lift and reduces COP.


Common Pitfalls:
Confusing capacity changes (kW of cooling) with efficiency; a system can deliver more capacity at higher speed but worse COP.


Final Answer:
Lower the higher (condensing) temperature

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