Difficulty: Easy
Correct Answer: 2 sin ωt
Explanation:
Introduction / Context:Lissajous figures on a CRO result from applying sinusoidal voltages to the horizontal (X) and vertical (Y) plates. The observed shape encodes the relative amplitude, frequency, and phase between the two signals, which is a classic laboratory method to compare frequencies and phases.
Given Data / Assumptions:
Concept / Approach:A straight line indicates zero phase difference or 180° phase difference with amplitude ratios defining slope. A 45° line with positive slope requires equal amplitudes and zero relative phase (or both inverted together). Therefore, the Y-input must match the X-input in both amplitude and phase: y(t) = 2 sin(ωt). Any phase shift would rotate or thicken the line into an ellipse, and an amplitude difference would change the slope away from 45°.
Step-by-Step Solution:
Desired slope = +1 ⇒ |Y|/|X| = 1.Straight line (not ellipse) ⇒ phase difference Δφ = 0° (or 180° for negative slope).Hence y(t) = 2 sin(ωt) gives a +45° line.Verification / Alternative check:
Plot x = 2 sin θ, y = 2 sin θ ⇒ y = x, a 45° line.Why Other Options Are Wrong:
±45° phase shifts produce an ellipse, not a perfect line; amplitude squaring (2^2) is dimensionally incorrect here.Common Pitfalls:
Confusing slope sign with phase sign; forgetting equal amplitudes are required for 45°.Final Answer:
2 sin ωt
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