The least multiple of $13$, which on dividing by $4$, $5$, $6$, $7$ and $8$ leaves remainder $2$ in each case is
Aptitude
HCF and LCM
Difficulty: Hard
Choose an option
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A840
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B842
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C2520
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D2522
Answer
Correct Answer: 2522
Explanation
### Concept & Logic
This is a dual-condition problem. The number must simultaneously be:
1. Of the format: $k \times \text{LCM} + R$ (to satisfy the remainder condition).
2. Perfectly divisible by a secondary target (in this case, $13$).
The core equation is:
$$\text{Number} = k \times \text{LCM}(a, b, c, \dots) + R$$
We must find the smallest positive integer $k$ ($1, 2, 3, \dots$) that makes the entire expression a perfect multiple of $13$.
### Step-by-Step Solution
* **Given:** Divisors are $4$, $5$, $6$, $7$, $8$. Remainder $R = 2$. Target multiple = $13$.
* **Find the LCM:**
Prime factors:
$4 = 2^2$
$5 = 5^1$
$6 = 2^1 \times 3^1$
$7 = 7^1$
$8 = 2^3$
$$LCM = 2^3 \times 3^1 \times 5^1 \times 7^1 = 8 \times 3 \times 5 \times 7 = 840$$
* **Formulate the number:**
The number takes the form: $N = 840k + 2$.
* **Satisfy the multiple of 13 condition:**
We need $(840k + 2)$ to be perfectly divisible by $13$.
To simplify testing, divide $840$ by $13$ and find the remainder.
$840 \div 13 = 64$ with a remainder of $8$.
Rewrite the expression using this remainder:
$840k + 2 = (13 \times 64k) + 8k + 2$
Since $(13 \times 64k)$ is already divisible by $13$, we only need to find a $k$ where the remaining part $(8k + 2)$ is divisible by $13$.
Test values of $k$:
If $k = 1$: $8(1) + 2 = 10$ (Not divisible by 13)
If $k = 2$: $8(2) + 2 = 18$ (Not divisible by 13)
If $k = 3$: $8(3) + 2 = 26$ (Perfectly divisible by 13, since $13 \times 2 = 26$)
* **Calculate final number:**
Substitute $k = 3$ back into the original formula:
$$N = 840(3) + 2 = 2520 + 2 = 2522$$
### Exam Strategy & Shortcut
**Direct Multiple Verification:**
Since the question asks for a "multiple of 13", the correct option MUST be perfectly divisible by $13$. Let's check the options directly:
(a) $840 \div 13 = 64.6$ (Not a multiple)
(b) $842 \div 13 = 64.7$ (Not a multiple)
(c) $2520 \div 13 = 193.8$ (Not a multiple)
(d) $2522 \div 13 = 194$ (Exact multiple)
Only option (d) satisfies the core condition of being a multiple of $13$. You can solve this in 10 seconds without calculating any LCMs!
### Common Pitfall
Students often stop at $k=1$ and calculate $840(1) + 2 = 842$, choosing it if it's an option. You must always ensure the secondary condition (divisible by 13) is met by checking your final number before finalizing the answer.
### Final Answer
**Therefore, the correct answer is 2522.**