In Java (Math.random casting), what value is assigned to i in the statement below? int i = (int) Math.random();

Introduction / Context:
The expression explores numeric casting in Java. Math.random() returns a double in the half-open range [0.0, 1.0). Casting such a value to an integer truncates toward zero, which determines the only possible result.

Given Data / Assumptions:

• Math.random() ∈ [0.0, 1.0).
• Cast to int performs truncation, not rounding.

Concept / Approach:
Any double d with 0.0 ≤ d < 1.0 becomes 0 when cast to int. There is no chance for 1 or negative numbers from this specific cast because the range excludes 1.0 and does not include negatives.

Step-by-Step Solution:

Verification / Alternative check:
If you intended random integers 0 or 1, you would write (int)(Math.random() * 2). For 1..10, use (int)(Math.random()*10) + 1.

Why Other Options Are Wrong:

• 1 or undetermined: contradict the defined range and truncation.
• Compile error: the code is legal.
• Negative: impossible from the domain.

Common Pitfalls:
Confusing truncation with rounding; forgetting that 1.0 is excluded from Math.random() range.

Final Answer:
i = 0