Difficulty: Easy
Correct Answer: Compilation fails.
Explanation:
Introduction / Context:
This snippet distinguishes between the APIs of immutable String and mutable StringBuilder/StringBuffer. It also highlights that ignoring the return value of substring does not change the original String, and that append is not a member of String at all.
Given Data / Assumptions:
d is declared as String.d.substring(1,7) is called but its result is discarded.d = "w" + d; creates a new String.d.append("woo") is attempted on a String.
Concept / Approach:
Only StringBuilder and StringBuffer provide append. Invoking append on a String is a compile-time error: cannot find symbol: method append(java.lang.String). If a mutable sequence was intended, declare StringBuilder d = new StringBuilder("bookkeeper"); and then use d.append(...).
Step-by-Step Solution:
d.append("woo") fails because String has no such method. Therefore the program does not run; no runtime output is produced.
Verification / Alternative check:
If we replaced line 4 with d = d + "woo";, output would be wbookkeeperwoo. If we used StringBuilder, we could build efficiently without intermediate strings.
Why Other Options Are Wrong:
append exists on String or that substring mutated the original; neither is true.
Common Pitfalls:
Treating Strings as mutable, or assuming substring changes the receiver. Always capture returned values from String operations.
Final Answer:
Compilation fails.
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