In Java, wrapper conversions and numeric promotions: predict the output printed by this try-catch code.\n\ntry {\n Float f1 = new Float("3.0");\n int x = f1.intValue();\n byte b = f1.byteValue();\n double d = f1.doubleValue();\n System.out.println(x + b + d);\n} catch (NumberFormatException e) {\n System.out.println("bad number");\n}

Introduction / Context:
This Java snippet tests knowledge of wrapper classes, primitive extraction methods, and numeric promotion rules during arithmetic and string output. A Float object is created from the string literal "3.0" and then converted to int, byte, and double before being summed and printed inside a try-catch that targets NumberFormatException.

Given Data / Assumptions:

• f1 is constructed as new Float("3.0").
• x = f1.intValue() returns 3.
• b = f1.byteValue() returns 3.
• d = f1.doubleValue() returns 3.0.
• System.out.println uses arithmetic addition because the first operator is numeric, not string concatenation.

Concept / Approach:
Autounboxing is not even required here because we explicitly call value methods. The expression x + b + d performs left-to-right evaluation with numeric promotion: int + byte becomes int, yielding 6, then 6 + double promotes to double, yielding 9.0. No parsing error occurs, so the catch block is not entered.

Step-by-Step Solution:

Verification / Alternative check:
If the code had used string concatenation like "" + x + b + d, the result would be the string "33.0". Because it starts with numeric types, Java performs arithmetic.

Why Other Options Are Wrong:

• bad number: No NumberFormatException occurs for "3.0".
• Compilation fails…: The code is syntactically valid.
• 3.03.0: That would require string concatenation from the first operand.

Common Pitfalls:
Assuming string concatenation, or expecting NumberFormatException for a valid decimal string.

Final Answer:
9.0