In Java (control flow with i++ and --j inside a do-while), what are the final values printed? int i = 1, j = 10; do { if(i++ > --j) /* Line 4 / { continue; } } while (i < 5); System.out.println("i = " + i + " and j = " + j); / Line 9 */

Introduction / Context: This problem exercises short, precise reasoning about post-increment and pre-decrement inside a conditional, plus the behavior of continue within a do-while loop. Understanding evaluation order is crucial to get the final values correct.

Given Data / Assumptions:

• Start with i = 1, j = 10.
• Condition checks i++ (returns old i, then increments) and --j (decrements then returns).
• continue skips to the while-condition check at the loop bottom.

Concept / Approach: Trace each iteration carefully and update i and j in the exact order the expression evaluates: left operand i++ first (post-increment), right operand --j second (pre-decrement), then compare. The body has no other state changes except potential continue (which still executes the loop condition afterward).

Step-by-Step Solution:

Verification / Alternative check: Because the if-condition never becomes true, continue never fires; only the implicit increments from the condition update i and j each time. Final: i = 5, j = 6.

Why Other Options Are Wrong:

• Other pairs assume a different number of iterations or reversed increment/decrement order.

Common Pitfalls: Forgetting that i++ returns the old value while still incrementing afterward; and that --j decrements before comparison.

Final Answer: i = 5 and j = 6