Difficulty: Easy
Correct Answer: 6 t/m^2
Explanation:
Introduction / Context:Active earth pressure represents the minimum lateral pressure mobilized when a retaining wall yields sufficiently away from the backfill. For cohesionless backfill with level ground, Rankine’s active coefficient provides a quick way to compute lateral stress with depth.
Given Data / Assumptions:
Concept / Approach:For cohesionless soil with horizontal backfill, Rankine active earth pressure coefficient is Ka = (1 − sin φ) / (1 + sin φ). The vertical overburden stress is σv = γ * z. The active horizontal pressure is σh = Ka * σv. Units must be consistent (t/m^3 * m → t/m^2).
Step-by-Step Solution:
Compute sin φ: sin 30° = 0.5.Ka = (1 − 0.5) / (1 + 0.5) = 0.5 / 1.5 = 1/3 ≈ 0.333.σv = γ * z = 1.8 * 10 = 18 t/m^2.σh = Ka * σv = (1/3) * 18 = 6 t/m^2.Verification / Alternative check:Using Coulomb with zero wall friction and vertical wall reduces to Rankine for level backfill; results match. A simple proportionality check: σh increases linearly with depth; at z = 0, σh = 0; at 10 m, the computed 6 t/m^2 is reasonable.
Why Other Options Are Wrong:
Common Pitfalls:Using degrees vs radians incorrectly; confusing kN/m^3 with t/m^3; forgetting that cohesionless c = 0 so no additive term appears.
Final Answer:6 t/m^2
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