Ordered relations: P ≥ Q = R > S > T. Which conclusions follow? I) P ≥ T; II) T < Q.

Introduction / Context:Convert the chain into relative ordering and test the targets P vs T and T vs Q.

Given Data / Assumptions:P ≥ Q, Q = R, R > S > T.

Concept / Approach:Because Q = R and R > T, certainly Q > T. Also P ≥ Q and Q > T ⇒ P ≥ T.

Step-by-Step Solution: T < S < R = Q ≤ P. Hence I) P ≥ T (true) and II) T < Q (true).

Verification / Alternative check:Plug values, e.g., T=1, S=2, R=3, Q=3, P=3 or 4. Both conclusions hold.

Why Other Options Are Wrong:Not “only one” or “neither”; both are valid.

Common Pitfalls:Overlooking that ≥ with a superior element still implies ≥ when compared to a strictly smaller element.

Final Answer:If both conclusions I and II follow