Ordered relations: V ≥ K > M = N, M > S, and T < K. Which conclusion(s) definitely follow? I) T < N; II) V = S.

Introduction / Context:
We compare T and V against the chain around K > M = N and M > S, with only T < K given for T.

Given Data / Assumptions:

• V ≥ K > M = N
• M > S
• T < K

Concept / Approach:
No direct relation ties T to N (other than both relating to K and M), and nothing ties V numerically to S; so we look for counterexamples.

Step-by-Step Solution:
I) T < N is not forced: pick K=10, M=N=5, T=9 (T < K but T > N). Premises hold, I fails. II) V = S is not forced: V ≥ K > M > S allows V and S to differ widely; equality is unjustified.

Verification / Alternative check:
Explicit assignment above shows both conclusions can fail; hence neither follows.

Why Other Options Are Wrong:
a/b/c/e assert conclusions not guaranteed by the premises.

Common Pitfalls:
Assuming T, being below K, must be below N as well; not true if N ≪ K & T close to K.

Final Answer:
If neither conclusion I nor II follows