Ordered relations: K < L, K > M, M ≥ N, N > O. Which conclusions follow? I) O < M; II) O < K.

Introduction / Context:
We trace strict and non-strict inequalities through a chain to compare O with M and K.

Given Data / Assumptions:

• K < L, K > M
• M ≥ N
• N > O

Concept / Approach:
N > O and M ≥ N together give M > O. Also, K > M and M > O imply K > O.

Step-by-Step Solution:
From N > O and M ≥ N ⇒ M > O (I true). From K > M and M > O ⇒ K > O ⇒ O < K (II true).

Verification / Alternative check:
Example: O=1, N=2, M=2 (≥N), K=3, L any >K. Both conclusions hold.

Why Other Options Are Wrong:
Since both conclusions are forced, “only I/II” or “neither” are incorrect.

Common Pitfalls:
Treating ≥ as possible equality with O; transitivity still shows strict greater-than above O.

Final Answer:
If both conclusions I and II follow