A man donates 5% of his income to a charitable organisation and then deposits 20% of the remaining amount in a bank. If the cash still left with him after these two actions is ₹1919, what was his original income in rupees?

Introduction / Context:
Percentage chain problems test your ability to apply successive percentage changes to a base value and track what remains. Here, part of the income is donated, then a further percentage of the remainder is deposited, and the leftover cash is given. We must reverse the steps to find the original income.

Given Data / Assumptions:

• Donation = 5% of income.
• Deposit = 20% of what remains after the donation.
• Cash finally left = ₹1919.
• All percentages are on their stated bases, and amounts are exact.

Concept / Approach:
If I is the income, after donating 5%, remaining = 95% of I = 0.95I. Then 20% of that is deposited, so cash left is 80% of the remainder, i.e., 0.80 * 0.95I = 0.76I. Set 0.76I equal to the known leftover ₹1919 and solve for I.

Step-by-Step Solution:

Verification / Alternative check:
From ₹2525: 5% donation = ₹126.25; remainder ₹2398.75. Deposit 20% = ₹479.75; cash left = ₹2398.75 − ₹479.75 = ₹1919. Correct.

Why Other Options Are Wrong:
2500 or 2300 would not reproduce ₹1919 after the two steps; 2558.60 arises from rounding mistakes when inverting 0.76.

Common Pitfalls:
Applying both percentages to the original income or adding percentages directly. Successive changes must be multiplicative.

Final Answer:
Rs. 2525