A town grows 4% annually, but emigration reduces the population by 1/2% each year. What is the overall percentage increase over 3 years?

Difficulty: Medium

Correct Answer: 10.8

Explanation:


Introduction / Context:
When two opposing percentage effects apply annually, combine them multiplicatively each year. Here, net annual growth equals +4% − 0.5% = +3.5%. Over multiple years, compound the net factor, not the separate components.


Given Data / Assumptions:

  • Birth/immigration growth = +4% ⇒ factor 1.04.
  • Emigration loss = −0.5% ⇒ factor 0.995.
  • Net yearly factor = 1.04 * 0.995 = 1.035 (i.e., +3.5%).
  • Time = 3 years.


Concept / Approach:
Overall multiplier after 3 years = (1.035)^3. Convert the multiplier to a percent increase by subtracting 1 and multiplying by 100.


Step-by-Step Solution:

Compute (1.035)^2 ≈ 1.071225.Multiply by 1.035 again: 1.071225 * 1.035 ≈ 1.108718.Overall increase ≈ 1.108718 − 1 = 0.108718 ≈ 10.87% ≈ 10.8% (to one decimal).


Verification / Alternative check:
Log-based approximation: 3 * 3.5% = 10.5% plus a small compounding addition (~0.35%) gives ~10.85%, consistent.


Why Other Options Are Wrong:
9.8 and 10 neglect compounding; 10.5 uses 3 × 3.5% without compounding; 11.5 overshoots realistic compounding.


Common Pitfalls:
Adding annual percentages linearly and ignoring multi-year compounding.


Final Answer:
10.8

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