Highway geometric design – differential grade on a curve after superelevation If the original longitudinal gradient is x% and, after providing proper superelevation along the curved portion, the effective gradient is y%, the differential grade along the curve equals:
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A(x - y)%
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B(x + y)%
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C(y - x)%
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D(x × y)%
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E(y + x)%
Answer
Correct Answer: (x - y)%
Explanation
Introduction / Context:On a curved highway with superelevation, the longitudinal profile perceived along an edge (or control line) can differ from the original centerline grade. Designers sometimes compute a “differential grade” to capture the change between the original gradient and the gradient after fully applying superelevation.
Given Data / Assumptions:
- x% = original (centerline) longitudinal gradient of the alignment.
- y% = effective gradient along the curve after providing superelevation.
- Sign convention: grades are algebraic; here we report the algebraic difference.
Concept / Approach:The differential grade is simply the algebraic difference between two grades describing the same reach: original and modified. It quantifies how the profile grade line effectively changes due to the cross fall transitioning to full superelevation through the curve.
Step-by-Step Solution:Define differential grade DG = original grade − modified grade.DG = x% − y%.Choose the option that reflects this algebraic difference.
Verification / Alternative check:In many layout computations, one may use absolute difference |x − y| to check vertical conflicts. The algebraic form (x − y)% is the clean expression.
Why Other Options Are Wrong:
- (x + y)% or (y + x)%: addition has no physical basis here.
- (y − x)%: sign-reversed relative to the definition above.
- (x × y)%: multiplication of percentages is not meaningful in this context.
Common Pitfalls:Ignoring sign convention or mixing up which line (edge vs. centerline) is being referenced. Always track which grade is being compared.
Final Answer:(x - y)%