Bearing conversion — special direction: If the whole circle bearing (WCB) of a line is 270°, what is its reduced (quadrantal) bearing expressed in the standard N/S θ E/W format?
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AS 90° W (due west)
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BN 90° E
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CS 45° W
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DN 60° W
Answer
Correct Answer: S 90° W (due west)
Explanation
Introduction / Context:Whole circle bearings (0°–360° clockwise from north) and reduced (quadrantal) bearings (N/S θ E/W with θ ≤ 90°) are two common ways to express directions. Converting correctly avoids plotting errors and miscommunication between field notes and computations.
Given Data / Assumptions:
- WCB = 270°.
- Reduced bearing uses a north or south reference with an acute angle to east or west.
- Angles are measured in degrees.
Concept / Approach:A WCB of 270° points exactly west. In reduced bearing notation, due west can be written as S 90° W or N 90° W; both are equivalent in direction because 90° west of north or south is the same line. To avoid ambiguity in multiple-choice settings, we pick one conventional form, typically S 90° W, and explicitly note it is due west.
Step-by-Step Solution:
Identify quadrant: 270° lies on the west axis.Express as reduced bearing with θ ≤ 90° toward west.Choose a standard form: S 90° W (due west).State final answer clearly.Verification / Alternative check:Sketch the axes: north at 0°, east at 90°, south at 180°, west at 270°. The line at 270° is unmistakably west, matching S 90° W.
Why Other Options Are Wrong:
- N 90° E: Due east, not west.
- S 45° W and N 60° W: Southwest and northwest directions, not exactly west.
Common Pitfalls:Writing “90° W” or “W 90°” which are not standard reduced-bearing formats; using N 90° W interchangeably in tests that require a single unique option.
Final Answer:S 90° W (due west)