Difficulty: Medium
Correct Answer: q^2 / g = (D1 * D2 * (D1 + D2)) / 2
Explanation:
Introduction / Context:Hydraulic jumps are rapid transitions from supercritical to subcritical flow that commonly occur in spillways, canal transitions, and energy dissipators. In open-channel hydraulics (civil engineering), their analysis relies on conservation of momentum in a control volume spanning the jump. This question tests recognition of the standard momentum relationship linking discharge per unit width q with upstream and downstream depths D1 and D2 for a rectangular channel.
Given Data / Assumptions:
Concept / Approach:The momentum function for a rectangular channel per unit width is M = q^2 / (g * y) + y^2 / 2. Equating M upstream (y = D1) and downstream (y = D2) yields the standard sequent-depth relation in momentum form, from which the required identity for q, D1, and D2 is obtained.
Step-by-Step Solution:
Upstream momentum: M1 = q^2 / (g * D1) + D1^2 / 2Downstream momentum: M2 = q^2 / (g * D2) + D2^2 / 2Set M1 = M2 → q^2/g * (1/D1 - 1/D2) = (D2^2 - D1^2)/2Left factor: (1/D1 - 1/D2) = (D2 - D1)/(D1 * D2)Right factor: (D2^2 - D1^2) = (D2 - D1)(D2 + D1)Cancel (D2 - D1) on both sides → q^2 / g * 1/(D1 * D2) = (D2 + D1)/2Rearrange → q^2 / g = (D1 * D2 * (D1 + D2)) / 2Verification / Alternative check:Dimensional check: q has units m^2/s; q^2/g has m^3. The right-hand side D1D2(D1+D2)/2 also has m^3. The relation is therefore dimensionally consistent.
Why Other Options Are Wrong:
Common Pitfalls:
Final Answer:q^2 / g = (D1 * D2 * (D1 + D2)) / 2
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