Hydraulic jump in a rectangular channel: If q is the discharge per unit width and D1 and D2 are the pre-jump and post-jump water depths respectively, which relationship between q, D1, and D2 holds true for momentum balance across the jump?

Difficulty: Medium

Correct Answer: q^2 / g = (D1 * D2 * (D1 + D2)) / 2

Explanation:


Introduction / Context:
Hydraulic jumps are rapid transitions from supercritical to subcritical flow that commonly occur in spillways, canal transitions, and energy dissipators. In open-channel hydraulics (civil engineering), their analysis relies on conservation of momentum in a control volume spanning the jump. This question tests recognition of the standard momentum relationship linking discharge per unit width q with upstream and downstream depths D1 and D2 for a rectangular channel.


Given Data / Assumptions:

  • Channel is prismatic and rectangular; width b is taken as 1 m so q = Q / b.
  • Flow is steady and incompressible, with hydrostatic pressure distribution outside the roller.
  • Energy losses in the roller are allowed; momentum (force) balance holds across the jump.


Concept / Approach:
The momentum function for a rectangular channel per unit width is M = q^2 / (g * y) + y^2 / 2. Equating M upstream (y = D1) and downstream (y = D2) yields the standard sequent-depth relation in momentum form, from which the required identity for q, D1, and D2 is obtained.


Step-by-Step Solution:

Upstream momentum: M1 = q^2 / (g * D1) + D1^2 / 2Downstream momentum: M2 = q^2 / (g * D2) + D2^2 / 2Set M1 = M2 → q^2/g * (1/D1 - 1/D2) = (D2^2 - D1^2)/2Left factor: (1/D1 - 1/D2) = (D2 - D1)/(D1 * D2)Right factor: (D2^2 - D1^2) = (D2 - D1)(D2 + D1)Cancel (D2 - D1) on both sides → q^2 / g * 1/(D1 * D2) = (D2 + D1)/2Rearrange → q^2 / g = (D1 * D2 * (D1 + D2)) / 2


Verification / Alternative check:
Dimensional check: q has units m^2/s; q^2/g has m^3. The right-hand side D1D2(D1+D2)/2 also has m^3. The relation is therefore dimensionally consistent.


Why Other Options Are Wrong:

  • Option B: Inverts the momentum relation; does not match momentum dimensions.
  • Option C: Uses depth difference squared; momentum balance does not produce (D2 - D1)^2 alone.
  • Option D: Sums squared depths; missing the multiplicative D1*D2 term from momentum derivation.
  • Option E: Harmonic-like form; again misses the (D1 + D2) multiplier in the numerator.


Common Pitfalls:

  • Confusing energy conservation with momentum conservation; energy is not conserved across a jump due to losses.
  • Forgetting that the momentum function for rectangular channels includes both velocity and hydrostatic terms.
  • Using discharge Q instead of unit discharge q without dividing by width.


Final Answer:
q^2 / g = (D1 * D2 * (D1 + D2)) / 2

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