Difficulty: Medium
Correct Answer: t = h / (G − 1)
Explanation:
Introduction / Context:
Hydraulic structures on pervious foundations are subjected to upward seepage pressures. The floor thickness must be adequate so that its submerged weight can counter the uplift to prevent heave or failure.
Given Data / Assumptions:
Concept / Approach:
Upward water pressure per unit area at the floor = γ_w * h. Downward resisting force per unit area due to the floor = (γ_floor − γ_w) * t = γ_w * (G − 1) * t. For safety at the limiting case, set resisting pressure equal to uplift pressure and solve for t.
Step-by-Step Solution:
Uplift pressure = γ_w * h.Resisting pressure = γ_w * (G − 1) * t.Equate: γ_w * (G − 1) * t = γ_w * h ⇒ t = h / (G − 1).
Verification / Alternative check:
The relation is dimensionally correct (both sides have length units). Additional safety may be provided by factors of safety or by drains/relief wells that lower h, reducing t required.
Why Other Options Are Wrong:
t = h * (G − 1): Overestimates thickness; not derived from equilibrium.t = h / G or G / h: Do not reflect the buoyancy reduction (G − 1) term.
Common Pitfalls:
Final Answer:
t = h / (G − 1)
Discussion & Comments