If $a + \frac{1}{b} = 1$ and $b + \frac{1}{c} = 1$, then $c + \frac{1}{a}$ is equal to
Aptitude
Simplification
Difficulty: Hard
Choose an option
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A$0$
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B$\frac{1}{2}$
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C$1$
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D$2$
Answer
Correct Answer: $1$
Explanation
### Concept & Formula
This problem involves a cyclic system of equations. The goal is to express both variables in the final expression ($c$ and $a$) in terms of a single intermediate variable (in this case, $b$) using the given equations, and then substitute them to find a constant value.
$$ \text{Substitution Goal: Express } c = f(b) \text{ and } \frac{1}{a} = g(b) $$
### Step-by-Step Solution
* **Given:**
* Equation 1: $a + \frac{1}{b} = 1$
* Equation 2: $b + \frac{1}{c} = 1$
* Target expression: $c + \frac{1}{a}$
* **Calculation:**
1. From Equation 1, solve for $\frac{1}{a}$ in terms of $b$.
First, isolate $a$: $a = 1 - \frac{1}{b}$.
Find a common denominator: $a = \frac{b - 1}{b}$.
Take the reciprocal to find $\frac{1}{a}$: $\frac{1}{a} = \frac{b}{b - 1}$.
2. From Equation 2, solve for $c$ in terms of $b$.
Isolate $\frac{1}{c}$: $\frac{1}{c} = 1 - b$.
Take the reciprocal to find $c$: $c = \frac{1}{1 - b}$.
To match the denominator of $\frac{1}{a}$, factor out a $-1$: $c = \frac{-1}{b - 1}$.
3. Substitute these expressions back into the target equation: $c + \frac{1}{a}$.
$c + \frac{1}{a} = \left(\frac{-1}{b - 1}\right) + \left(\frac{b}{b - 1}\right)$.
4. Since they share a common denominator, add the numerators.
$\frac{-1 + b}{b - 1} = \frac{b - 1}{b - 1}$.
5. Simplify the fraction. Any non-zero number divided by itself is $1$.
Result is $1$.
### Exam Strategy & Shortcut
Use the Value Assumption strategy. Pick a number for $b$ that makes calculation easy, such as $b = 2$.
If $b = 2$, then from Equation 1: $a + \frac{1}{2} = 1 \implies a = \frac{1}{2}$.
If $b = 2$, then from Equation 2: $2 + \frac{1}{c} = 1 \implies \frac{1}{c} = -1 \implies c = -1$.
Now, calculate the target $c + \frac{1}{a}$:
Target = $(-1) + \frac{1}{\frac{1}{2}} = -1 + 2 = 1$.
This confirms the answer instantly without complex algebraic manipulation.
### Common Pitfall
When rearranging terms, students often mishandle reciprocals, incorrectly assuming that if $a = 1 - \frac{1}{b}$, then $\frac{1}{a} = 1 - b$. You must combine the terms into a single fraction before taking the reciprocal.
### Final Answer
Therefore, the correct answer is 1.