If $x + y + z = 0$, then $x^2 + xy + y^2$ equals
Aptitude
Simplification
Difficulty: Medium
Choose an option
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A$y^2 + yz + z^2$
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B$y^2 - yz + z^2$
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C$z^2 - zx + x^2$
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D$z^2 + zx + x^2$
Answer
Correct Answer: $y^2 + yz + z^2$
Explanation
### Concept & Strategy
When given the cyclic condition $x + y + z = 0$, expressions of the form $x^2 + xy + y^2$ exhibit a unique mathematical symmetry. By expressing one variable in terms of the other two, we can seamlessly convert the expression into terms of $y$ and $z$.
### Step-by-Step Solution
Given:
$x + y + z = 0$
We need to find the equivalent of: $x^2 + xy + y^2$
**Method: Algebraic Substitution**
From the given condition, isolate $x$:
$x = -(y + z)$
Now, substitute this expression for $x$ into our target formula:
$= [-(y + z)]^2 + [-(y + z)]y + y^2$
Expand the terms:
The square of a negative is positive, so $[-(y + z)]^2 = (y + z)^2 = y^2 + 2yz + z^2$.
Distribute the $-y$ in the middle term: $-y(y + z) = -y^2 - yz$.
Combine everything together:
$= (y^2 + 2yz + z^2) - y^2 - yz + y^2$
Combine like terms:
- The $y^2$ terms: $y^2 - y^2 + y^2 = y^2$
- The $yz$ terms: $2yz - yz = yz$
- The $z^2$ terms: $+ z^2$
Result:
$= y^2 + yz + z^2$
*(Note: Due to the symmetrical nature of $x+y+z=0$, the expression $x^2+xy+y^2$ is also mathematically equal to $z^2+zx+x^2$, which is option D. However, direct consecutive cyclic substitution conventionally yields option A first.)*
### Exam Strategy & Shortcut
**Value Verification:** Pick three numbers that sum to zero.
Let $x = 1, y = 2, z = -3$.
Calculate the target expression $x^2 + xy + y^2$:
$= (1)^2 + (1)(2) + (2)^2 = 1 + 2 + 4 = 7$.
Now, plug these values into the options to find which equals 7:
(a) $y^2 + yz + z^2 = (2)^2 + (2)(-3) + (-3)^2 = 4 - 6 + 9 = 7$. (Matches)
(b) $y^2 - yz + z^2 = 4 - (-6) + 9 = 19$. (Incorrect)
(c) $z^2 - zx + x^2 = 9 - (-3)(1) + 1 = 13$. (Incorrect)
(d) $z^2 + zx + x^2 = 9 + (-3)(1) + 1 = 7$. (Also matches)
As verified algebraically, A and D are identical in value. Usually, A is the intended direct cyclic derivation.
### Common Pitfall
Students often try to blindly square the equation $(x + y + z)^2 = 0$ to get $x^2 + y^2 + z^2 + 2xy + 2yz + 2zx = 0$ and then get stuck trying to manipulate this massive string into $x^2 + xy + y^2$. Targeted substitution is much cleaner.
### Final Answer
Therefore, the correct answer is **$y^2 + yz + z^2$**.