The sum of the weights of $A$ and $B$ is 80 kg. Half of the weight of $A$ is equal to $\frac{5}{6}$ times the weight of $B$. Find the weight of $B$.
Aptitude
Simplification
Difficulty: Medium
Choose an option
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A20 kg
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B30 kg
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C40 kg
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D60 kg
Answer
Correct Answer: 30 kg
Explanation
### Concept & Logic
Translate the textual relationships into a system of linear equations. Use substitution or the ratio method to isolate and solve for the target variable.
### Step-by-Step Solution
* **Given:**
* $A + B = 80$
* $\frac{1}{2}A = \frac{5}{6}B$
* **Calculation:**
1. Isolate $A$ in the second equation by multiplying both sides by 2:
$A = 2 \times (\frac{5}{6})B$
$A = \frac{10}{6}B = \frac{5}{3}B$
2. Substitute this expression for $A$ into the first equation:
$\frac{5}{3}B + B = 80$
3. Find a common denominator to add the terms:
$\frac{5}{3}B + \frac{3}{3}B = 80$
$\frac{8}{3}B = 80$
4. Solve for $B$:
$B = 80 \times \frac{3}{8}$
$B = 10 \times 3 = 30$ kg
### Exam Strategy & Shortcut
The fastest way to solve this is using the Ratio Method.
From $\frac{A}{2} = \frac{5B}{6}$, we can deduce the ratio of their weights: $\frac{A}{B} = \frac{10}{6} = \frac{5}{3}$.
This means $A$ is 5 parts and $B$ is 3 parts.
Total parts = $5 + 3 = 8$ parts.
Total weight is 80 kg, so 1 part = $80 / 8 = 10$ kg.
The weight of $B$ is 3 parts, which equals $3 \times 10 = 30$ kg.
### Common Pitfall
A common trap is accidentally calculating the weight of $A$ instead of $B$ at the very end. 1 part is 10 kg, making $A$ equal to 50 kg. If 50 was an option, many would rush to select it. Always double-check which variable the question is asking for.
### Final Answer
**Therefore, the correct answer is 30 kg.**