Osmotic pressure control: which action will increase the osmotic pressure (π) of a solution, all else being equal?

Difficulty: Easy

Correct Answer: none of these

Explanation:


Introduction / Context:
Osmotic pressure is critical in membrane separations, food preservation, and biological cells. It scales with solute particle concentration and absolute temperature.



Given Data / Assumptions:

  • Dilute solution obeying van’t Hoff relation: π = i * C * R * T.
  • i is the van’t Hoff factor; C is molar concentration; T is absolute temperature.
  • Closed system with a semipermeable membrane conceptually present.



Concept / Approach:
From π = i C R T, increasing π requires increasing either i (more dissociation), C (more moles of solute per unit volume), or T (higher temperature). The listed actions either decrease T, decrease C, or effectively dilute the solution—none of which raise π.



Step-by-Step Solution:
Option (a): lowering temperature reduces T → π decreases.Option (b): increasing volume at fixed solute moles reduces C → π decreases.Option (c): dilution reduces C → π decreases.Thus, none of the listed actions increase π.



Verification / Alternative check:
To increase π in practice: add solute (increase C), choose a solute with higher dissociation i, or raise the solution temperature.



Why Other Options Are Wrong:
Each proposed action moves π in the opposite direction predicted by the van’t Hoff equation.



Common Pitfalls:
Assuming vessel expansion increases pressure (it lowers concentration instead); confusing osmotic pressure with hydrostatic pressure.



Final Answer:
none of these


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