Calculate the standard heat of formation of carbon monoxide (CO) from given combustion data.
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A-109.5
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B+109.5
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C+180
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D+100
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E-180
Answer
Correct Answer: -109.5
Explanation
Introduction / Context:Hess’s law enables computation of heats of formation from tabulated reaction enthalpies. Here, we deduce the formation enthalpy of CO using two combustion reactions leading to CO2.
Given Data / Assumptions:
- C + O2 → CO2, ΔH = −394 kJ/kg·mole.
- CO + 1/2 O2 → CO2, ΔH = −284.5 kJ/kg·mole.
- Target: C + 1/2 O2 → CO (standard heat of formation of CO).
Concept / Approach:Use Hess’s law by subtracting the CO combustion step from the carbon combustion step to isolate the formation of CO from its elements.
Step-by-Step Solution:Write target: C + 1/2 O2 → CO (ΔH_f,CO = ?).Subtract (CO + 1/2 O2 → CO2, −284.5) from (C + O2 → CO2, −394).Resulting reaction: C + 1/2 O2 → CO with ΔH = −394 − (−284.5) = −109.5 kJ/kg·mole.
Verification / Alternative check:Alternatively, use ΔH_f(CO2) = −394 and ΔH_rxn(CO→CO2) = ΔH_f(CO2) − ΔH_f(CO) to solve for ΔH_f(CO) = −394 − (−284.5) = −109.5.
Why Other Options Are Wrong:+109.5 has wrong sign; +180 and +100 are inconsistent with given data; −180 does not follow from the provided enthalpies.
Common Pitfalls:Forgetting to reverse/sign-change when subtracting reactions; mixing per-mole bases (ensure kg·mole basis is consistent).
Final Answer:-109.5