Thick-walled cylinder under internal pressure: where along the wall thickness is the hoop (circumferential) stress the greatest—at the inner radius or elsewhere?
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ATrue
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BFalse
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COnly true for thin shells
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DOnly true when external pressure acts as well
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EDepends only on Poisson’s ratio
Answer
Correct Answer: True
Explanation
Introduction / Context:In pressure vessel design, understanding how circumferential (hoop) stress varies through the wall of a thick cylinder is essential for safe sizing and material selection. Thick-cylinder behavior differs from thin-shell formulas because stresses vary significantly from the inside surface to the outside surface.
Given Data / Assumptions:
- Cylindrical vessel with inner radius and outer radius, subjected to internal pressure p only.
- Isotropic, homogeneous, linearly elastic material.
- No thermal gradients or external pressure unless stated.
Concept / Approach:Lame’s equations govern radial and hoop stresses in thick cylinders. For internal pressure only, the radial stress is most compressive (−p) at the inner surface and approaches zero at the outer surface. The hoop stress is tensile and attains its maximum at the inner surface, decreasing towards the outer surface.
Step-by-Step Solution:
Use Lame form: sigma_r = A − B/r^2, sigma_theta = A + B/r^2Apply boundary conditions: sigma_r(inner) = −p, sigma_r(outer) = 0Solve for A and B, then evaluate sigma_theta(r).Result: sigma_theta is largest at r = inner radius and reduces with increasing r.Verification / Alternative check:Plot sigma_theta versus r from the inner to outer surface. The curve peaks at the inner wall for an internally pressurized cylinder, matching standard design charts.
Why Other Options Are Wrong:False/conditional options conflict with Lame’s solution; dependence on Poisson’s ratio does not overturn the location of maximum hoop stress.
Common Pitfalls:Using thin-wall formula sigma_h = p d / (2 t) when D/t is small; neglecting through-thickness stress variation and inner-wall peaking.
Final Answer:
True