Difficulty: Medium
Correct Answer: Correct
Explanation:
Introduction / Context:
Digital clock projects in HDL (Hardware Description Language) commonly implement hour, minute, and second counters with well-defined roll-over conditions. The transition from 11:59:59 to 12:00:00 in a 12-hour clock requires special detection logic so that hours advance from 11 to 12, not to 00, preserving familiar timekeeping conventions.
Given Data / Assumptions:
Concept / Approach:
In HDL, roll-over is handled by decoding a terminal count and issuing a synchronous load or increment. An AND gate (or equivalent Boolean term) often watches a combination of states: seconds = 59, minutes = 59, hours = 11. When that condition is true at the next clock edge, the control logic forces seconds and minutes to 00 and loads hours with 12 rather than incrementing to 00.
Step-by-Step Solution:
Detect terminal count: (sec == 59) * (min == 59) * (hours == 11).Include sub-decodes: tens_of_hours == 1 and ones_of_hours == 1.On the edge-triggered clock, execute: sec := 00; min := 00; hours := 12.Else, operate normally: seconds increment; cascade to minutes and hours on overflow.
Verification / Alternative check:
Simulate a timing wave: advance time through 11:59:58 → 11:59:59 → 12:00:00. Confirm synchronous loads occur only on the clock edge when the AND condition is true.
Why Other Options Are Wrong:
“Incorrect” ignores the standard 12-hour roll-over logic. “Only for 24-hour clocks” is inverted; 24-hour uses 23→00. The conditions do not require “minutes tens = 0.” “Asynchronous clocks” are not required; synchronous, edge-triggered design is the norm.
Common Pitfalls:
Forgetting to load 12 after 11, accidentally rolling to 00, or mixing asynchronous resets with synchronous loads causing glitches.
Final Answer:
Correct
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