Difficulty: Medium
Correct Answer: Mr. Kirk
Explanation:
Introduction / Context:This scheduling logic question involves two swaps across a Monday–Thursday window. The challenge is to track original assignments and then apply trades to deduce the person who ends up on Tuesday.
Given Data / Assumptions:
Concept / Approach:First recover every original day by elimination. Then apply each trade to swap days between the two named people. The worker not involved in a particular trade retains their current day after that trade.
Step-by-Step Solution:
Original schedule: Johnson = Mon; Carter = Wed; Kirk = Thu; Falk = Tue (by elimination).Trade 1 (Johnson ↔ Carter): Johnson → Wed; Carter → Mon; Falk remains Tue; Kirk remains Thu.Trade 2 (Falk ↔ Kirk): Falk → Thu; Kirk → Tue; Johnson remains Wed; Carter remains Mon.Final schedule: Mon = Carter; Tue = Kirk; Wed = Johnson; Thu = Falk.Verification / Alternative check:
Check uniqueness (each day has exactly one worker) and that each trade simply swapped the two names’ days—both conditions hold.Why Other Options Are Wrong:
Carter moved to Monday; Johnson to Wednesday; Falk to Thursday. None of these is Tuesday.“No one worked Tuesday” contradicts the setup that each day has one worker.Common Pitfalls:
Forgetting to assign Falk’s original day by elimination before executing the second trade.Final Answer:Mr. Kirk
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